[810500+tan theta=1" then hovit "8" the "89],[(a-2b+c)x+(b-2c+a)x+(c-2a+b)=0" is "]

If sec theta + tan theta=1 , then root of the equation (a-2b+c)x^(2) + (b-2c+a)x + (c-2a+b)=0 is:

If sec theta+tan theta=1, then root of the equation (a-2b+c)x^(2)+(b-2c+a)x+(c-2a+b)=0 is :

If sec theta+tan theta=1, then one root of the eqection a(b-c)x^(2)+b(c-a)x+c(a-b)=0 is (A) tan theta(B)sec theta(C)cos theta(D)sin theta

If a b+b c+c a=0, then solve a(b-2c)x^2+b(c-2a)x+c(a-2b)=0.

If a b+b c+c a=0, then solve a(b-2c)x^2+b(c-2a)x+c(a-2b)=0.

If a b+b c+c a=0, then solve a(b-2c)x^2+b(c-2a)x+c(a-2b)=0.

If a , b , c are positive numbers such that a gt b gt c and the equation (a+b-2c)x^(2)+(b+c-2a)x+(c+a-2b)=0 has a root in the interval (-1,0) , then

If a , b , c are positive numbers such that a gt b gt c and the equation (a+b-2c)x^(2)+(b+c-2a)x+(c+a-2b)=0 has a root in the interval (-1,0) , then

If a , b , c are positive numbers such that a gt b gt c and the equation (a+b-2c)x^(2)+(b+c-2a)x+(c+a-2b)=0 has a root in the interval (-1,0) , then

If a , b , c are positive numbers such that a gt b gt c and the equation (a+b-2c)x^(2)+(b+c-2a)x+(c+a-2b)=0 has a root in the interval (-1,0) , then