[" Iuustration "27.15" The median "AD" of the triangle "ABC" is "],[" bisected at "E" and "BE" meets "AC" at "F" .Find "AF:FC" ."]

The median AD of the triangle ABC is bisected at E. BE meets AC in F then AF : AC is

the median AB of Delta ABC is bisected at Eand BE is produced to meet the side AC in f.then the ratio AF:FC=

The median AD to DeltaABC is bisected at E and BE is produced to meet the side AC in F. Show that bar(AF)=1/3bar(AC)

A median drawn from the vertex from the A of a triangle ABC is bisected at E . BE meets AC in F such that AF:AC = 1 : n where n is-

The median AD of a triangle ABC is bisected at F, and BF is produced to meet the side AC in P. If AP = lamdaAC , then what is the value of lamda .?

E is any point on median AD of a triangle ABC . Show that ar (ABE) = ar (ACE).

In the fig. AD is a median of triangle ABC and E is the mid point of AD, also BE meets AC in F. prove that AF=1/3AC

The median AD of triangle ABC is bisected at F and BF is produced to meet the side AC in P. If AP=lambda AC then what is the value of lambda