The level of water in a tank is 5 m high. A hole of area of cross section 1 `cm^(2)` is made at the bottom of the tank. The rate of leakage of water for the hole in `m^(3)s^(-1)` is `(g=10ms^(-2))`

The level of water in a tank is 5 m high . A hole of the area 10 cm^2 is made in the bottom of the tank . The rate of leakage of water from the hole is

The level of water in a tank is 5 m high . A hole of the area 10 cm^2 is made in the bottom of the tank . The rate of leakage of water from the hole is

The level of water in a tank is 5m high.A hole of area 1cm^2 is made in the bottom of the tank. The rate of leakage of water from the hole is (g=10ms^(-2)

The water level on a tank is 5m high. There is a hole of 1 cm^(2) cross-section at the bottom of the tank. Find the initial rate with which water will leak through the hole. ( g= 10ms^(-2) )

The water level on a tank is 5m high. There is a hole of 1 cm^(2) cross-section at the bottom of the tank. Find the initial rate with which water will leak through the hole. ( g= 10ms^(-2) )

The water level in a tank is 5m high. There is a hole of 1cm^2 cross section at the bottom of the tank through which water is licking. Find out the initial rate of leakage of water in metre^3//sec unit. (Take g=10m//sec^2 )

A tank of height 5m is full of water. There is a hole of cross-sectional area 1cm^(2) at its bottom. The volume of water that will come out from this hole per second is (g=10m//s^(2))

There is a hole at the side-bottom of a big water tank. The area of the hole is 4mm^(2) to it a pipe is connected. The upper surface of water is 5 m above the hole. The rate of flow of water through the pipe is (in m^(3)s^(-1))(g=10ms^(-2))