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A block of mass m = 2kg is resting on a ...

A block of mass `m = 2kg` is resting on a inclined plane of inclination `30^(@)` as shown in figure The coefficient of friction between the block and the plane is `mu = 0.5` what minimum force F (in newton) should be applied perpendicular to the plane on the block so that the does not slip on the plane?

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A block of mass m=2kg is resting on a rough inclined plane of inclination of 30^(@) as shown in figure. The coefficient of friction between the block and the plane is mu=0.5 . What minimum force F should be applied perpendicular to the plane on the block, so that blocks does not slip on the plane? (g=10m//s^(2))

A block of mass m = 2kg is resting on a inclined plane of inclination 30^(@) The coefficient of friction between the block and the plane is mu = 0.5 what minimum force F (in newton) should be applied perpendicular to the plane on the block so that the does not slip on the plane?

A block of mass m=2kg is resting on a rough inclined plane of inclination plane of inclination 30^(@) as shown in figure. The coefficient of friction between the block and the plane is mu=0.5 . What minimum force F should be applied perpendicular to the plane on the block, so that blocks does not slip on the plane? (g=10m//s^(2))

A block of mass m=2kg is resting on a rough inclined plane of inclination plane of inclination 30^(@) as shown in figure. The coefficient of friction between the block and the plane is mu=0.5 . What minimum force F should be applied perpendicular to the plane on the block, so that blocks does not slip on the plane? (g=10m//s^(2))

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