In a photon electric experiment set upm , photons of energy `5 eV` falls on the cathode having work function `3 eV` (a) if the seturation current is ` i= 4 mu A` for intensity `10^(-5) W//m^(2)`, then plot a graph between anode potential and current (b) Also draw a graph for intensity of incident radiation `2 xx 10^(-5) W//m^(2)`

In a photoelectric experiment set up, photons of energy 5 eV falls on the cathode having work function 3 eV (a) if the saturation current is i= 4 mu A for intensity 10^(-5) W//m^(2) , then plot a graph between anode potential and current (b) Also draw a graph for intensity of incident radiation 2 xx 10^(-5) W//m^(2)

In a photoelectric experiment set up, photons of energy 5 eV falls on the cathode having work function 3 eV (a) if the saturation current is i= 4 mu A for intensity 10^(-5) W//m^(2) , then plot a graph between anode potential and current (b) Also draw a graph for intensity of incident radiation 2 xx 10^(-5) W//m^(2)

A photon energy 3.4 eV is incident on a metal having work function 2 eV . The maximum K.E. of photoelectrons is equal to

In a photoelectric effect experiment, photons of energy 5 eV are incident on the photocathode of work function 3eV . For photon intensity I_(A)=10^(15)m^(-2)s^(-1) , saturation current of 4.0 mu A is obtained. Sketch the variation of photocurrent i_(p) against the anode voltage V_(a) in the figure below for photon intensity I_(A) ( curve A ) and I_(B)=2xx10^(15)m^(-2)s^(-1) (curve B ) ( in JEE graph was to be drawn in the answer sheet itself.)

In a photoelectric effect experiment, photons of energy 5 eV are incident on the photocathode of work function 3eV . For photon intensity I_(A)=10^(15)m^(-2)s^(-1) , saturation current of 4.0 mu A is obtained. Sketch the variation of photocurrent i_(p) against the anode voltage V_(a) in the figure below for photon intensity I_(A) ( curve A ) and I_(B)=2xx10^(15)m^(-2)s^(-1) (curve B ) ( in JEE graph was to be drawn in the answer sheet itself.)

Photons of energy 1.5 eV and 2.5 eV are incident on a metal surface of work function 0.5 eV. What is the ratio of the maximum kinetic energy of the photoelectrons ?

Two differenct photons of energies, 1 eV and 2.5 eV, fall on two identical metal plates having work function 0.5 eV, Then the ratio of maximum KE of the electrons emitted from the two surface is -

Two photons of energy 2.5 eV and 3.5 eV fall on a metal surface on work function 1.5 eV. The ratio of the maxium velocities of the photoelectrons emitted from the metal surface is

In a photo electric experiment, photon of energy 5 eV are incident on a metal surface. They liberate electrons which are just stopped by an electrode at a potential of -3.5V with respect to the metal. The work function of the metal in eV is