Let `f(x) :R->R,f(x)={(2x+alpha^2,xge2),((alpha x)/2+10,x lt 2))` If `f(x)` is onto function then `alpha` belongs to (A) `[1,4]` (B) `[-2,3]` (C) `[0,3]` (D) `[2,5]`

If f:Rto(1,10) , where f(x)=(x^(2)+1-alpha)/(x^(2)+2) is an onto function, then the value alpha is

If f:R rarr R,f(x)=(alpha x^(2)+6x-8)/(alpha+6x-8x^(2)) is onto then alpha in

Let f:R rarr R be defined by f(x)=2+alpha x,alpha!=0 , If f(x)=f^(-1)(x) , for all x in R , then alpha equals

Let f(x)={((alpha cotx)/x+beta/x^2,0<|x|lt=1),(1/3,x=0)) If f(x) is continuous at x=0 then the value of alpha^2+beta^2 is 1 b. 2 c. 5 d. 9

If f:R rarr[a,6] defined by f(x)=(x^(2)-2x+d)/(x^(2)+3x+d) is an onto function,then

Let g(x)=x^(2)-2x-2 and f(x)=x^(2)+x+alpha . If f(g(x))=0 has no real solution then the set of values of alpha is.

Let g(x)=|(f(x+alpha), f(x+2a), f(x+3alpha)), f(alpha), f(2alpha), f(3alpha),(f\'(alpha),(f\'(2alpha), f\'(3alpha))| , where alpha is a constant then Lt_(xrarr0(g(x))/x= (A) 0 (B) 1 (C) -1 (D) none of these