Let `f:R->[1,oo)` be defined as `f(x)=log_10(sqrt(3x^2-4x+k+1)+10)` If f(x) is surjective then k =

Let f:R rarr[1,oo) be defined as f(x)=log_(10)(sqrt(3x^(2)-4x+k+1)+10) If f(x) is surjective then k=

Let f:R rarr[2,oo) be a function defined as f(x)=x^(2)-12ax+15-2a+36a^(2) . If f(x) is surjective on R, then the value of a is equal to

If f:R rarrA defined as f(x)=tan^(-1)(sqrt(4(x^(2)+x+1))) is surjective, then A is equal to

Let f:[-00,0)->(1, oo ) be defined as f(x)=(1+sqrt(-x))-(sqrt(-x)-x) then f(x) is (A) injective but not surjective (B) injective as well as surjective (C) neither injective nor surjective (D) surjective nut not injective

Let f:[-oo,0]rarr[1,oo) be defined as f(x)=(1+sqrt(-x))-(sqrt(-x)-x), then

Let f: R->R be defined as f(x)=x^2+1 . Find: f^(-1)(10)

If the function f: R -{1,-1} to A definded by f(x)=(x^(2))/(1-x^(2)) , is surjective, then A is equal to (A) R-{-1} (B) [0,oo) (C) R-[-1,0) (D) R-(-1,0)

Let f:(e,oo)rarr R be defined by f(x)=ln(ln(In x)), then

Let f be a function defined from R rarr R as f(x)={ x+p^(2) x 2} If f(x) is surjective function then sum of all possible integral values of p for p in [0 ,10] is