Position of particle moving along x-axis is given as `x=2+5t+7t^(2)` then calculate :

The position of a particle moving along x-axis is given by x = 10t - 2t^(2) . Then the time (t) at which it will momentily come to rest is

The position of a particle moving along x-axis is given by x = 10t - 2t^(2) . Then the time (t) at which it will momentily come to rest is

Position of a particle moving along x-axis is given by x=2+8t-4t^(2) . The distance travelled by the particle from t=0 to t=2 is:-

Position of a particle moving along x-axis is given by x=2+8t-4t^(2) . The distance travelled by the particle from t=0 to t=2 is:-

Position of a particle moving along x-axis is given by x=2+8t-4t^(2) . The distance travelled by the particle from t=0 to t=2 is:-

The displacement (in metre) of a particle moving along x-axis is given by x=18t +5t^(2) . Calculate (i) the instantaneous velocity t=2 s (ii) average velocity between t=2 s to t=3 s (iii) instantaneous acceleration.

The displacement (in metre) of a particle moving along x-axis is given by x=18t +5t^(2) Calculate (i) instantaneous acceleration.

The displacement of particle moving along x-axis is given by x=6t+12t^(2) , calculate the instantaneous velocity at t=0 and t=2s.

The displacement (in metre) of a particle moving along x-axis is given by x=18t +5t^(2). Calculate (i) the instantaneous velocity t=2 s (ii) average velocity between t=2 s to t=3 s (iii) instantaneous acceleration.

If the velocity of a particle moving along x-axis is given as v=(3t^(2)-2t) and t=0, x=0 then calculate position of the particle at t=2sec.