If origin is shifted to (-2, 3) then transformed equation of curve `x^2 +2y-3=0` w.r.t. to (0, 0) is

When the origin is shifted to the point (2 , 3) the transformed equation of a curve is x^(2) + 3xy - 2y^(2) + 17 x - 7y - 11 = 0 . Find the original equation of curve.

When the origin is shifted to the point (5,-2) then the transformed equation of the curve xy+2x-5y+11=0 is XY=K then k is

If origin is shifted to the point (-1,2) then what will be the transformed equation of the curve 2x^(2)+y^(2)-3x+4y-1=0 in the new axes ?

If origin is shifted to the point (-1,2) then what will be the transformed equation of the curve 2x^(2)+y^(2)-3x+4y-1=0 in the new axes ?

When (0,0) shifted to (2, -2) the transformed equation of (x - 2)^(2) + (y + 2)^(2) = 9 is

Image of (2,3) w.r.t (0,0) is