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Consider f" ":" "{1," "2," "3}->{a ," "b...

Consider `f" ":" "{1," "2," "3}->{a ," "b ," "c}` given by `f(1)" "=" "a` , `f(2)" "=" "b` and `f(3)" "=" "c` . Find `f^(-1)` and show that `(f^(-1))^(-1)=" "f` .

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