Calculate the energy generated in kWh, when 100g of `._(3)Li(7)`. are converted into `._(2)He(4)` by proton bombardment. Given mass of `._(3)Li(7)=7.0183a.m.u ,` mass of `._(2)He(4)=4.0040a.m.u`, mass of `._(1)H(1)atom=1.0081a.m.u.`

Calculate the energy liberated in kWh, where 100 g of "_3Li^7 are converted into "_2He^4 by proton bombbardment. Given mass of "_3Li^7=7.0183 u , mass of "_2He^4=4.0040 u and mass of "_1H^1 = 1.0081 u .

Calculate the energy released in kilowatt-hours when 100g of ._(3)^(7)Li are converted into ._(2)^(4)He by proton bombardment. Mass of ._(3)^(7)Li = 7.0183 am u , mass of proton = 1.0081 amu. Write down the nuclear reaction.

The binding energy per nucleon for ._(3)Li^(7) will be, if the mass of ._(3)Li^(7) is 7.0163 a.m.u.

Calculate the binding energy of a deutron. Given that mass of proton = 1.007825 a.m.u mass of neutron = 1.008665 a.m.u . mass of a deutron = 2.014103 a.m.u .

In a nuclear reaction, alpha+"_(7)N^(14)toX+p When nitrogen atoms are bombarded by 7.7 Me V alpha- particles, protons are ejected with a kinetic energy of 5.5 MeV . The Q- value of the reaction is -1.26 MeV ( a ) Find the atomic mass of X in amu, identify the element X . ( b ) Find the angle phi between the direction of motion of proton and alpha- particle. Given the atomic mass of "_(1)H^(1)=1.00814 a.m.u. , atomic mass of "_(7)N^(14)=14.00752 amu , and atomic mass of "_(2)He^(4)=4.0038 a.m.u.

In a nuclear reaction, alpha+"_(7)N^(14)toX+p When nitrogen atoms are bombarded by 7.7 Me V alpha- particles, protons are ejected with a kinetic energy of 5.5 MeV . The Q- value of the reaction is -1.26 MeV ( a ) Find the atomic mass of X in amu, identify the element X . ( b ) Find the angle phi between the direction of motion of proton and alpha- particle. Given the atomic mass of "_(1)H^(1)=1.00814 a.m.u. , atomic mass of "_(7)N^(14)=14.00752 amu , and atomic mass of "_(2)He^(4)=4.0038 a.m.u.

Calculate the energy released in the following: ._(1)H^(2) + ._(1)H^(3) rarr ._(2)He^(4) + ._(0)n^(1) (Given masses : H^(2) = 2.014, H^(3) = 3.016, He = 4.003, n = 1.009 m_(u))

Calculate the energy released in the following: ._(1)H^(2) + ._(1)H^(3) rarr ._(2)He^(4) + ._(0)n^(1) (Given masses : H^(2) = 2.014, H^(3) = 3.016, He = 4.003, n = 1.009 m_(u))