If a body is thrown with a speed of `19.6m//s` making an angle of `30^(@)` with the horizontal,then the time of flight is

From the top of a cliff 73.5 m a body is projected with a velocity of 19.6 m/s at an angle of 30^@ with the horizontal. Determine the time of flight, the distance from the foot of the tower and velocity with which the body strike the ground. g =9.8 m/ s^2

A body is thrown with a velocity of 9.8 m//s making an angle of 30^(@) with the horizontal. It will hit the ground after a time

A body is thrown with a velocity of 9.8 m//s making an angle of 30^(@) with the horizontal. It will hit the ground after a time

A body is thrown with a velocity of 9.8 m/s making an angle of 30^(@) with the horizontal. It will hit the ground after a time

A particle is thrown with speed of 50 m//s at an angle of projection 37^(@) with the horizontal. Find (a) the time of flight, (b) the maximum height attained and ( c) the horizontal range. (sin 37^(@) = (3)/(5), cos 37^(@) = (4)/(5))