Here are four descriptions of the position (in meters) of a puck as it moves in an xy plane:
(1) `x=-3t^(2)+4t-2andy=6t^(2)-4t`
(2) `x=-3t^(3)-4t andy=-5t^(2)+6`
(3) `vecr=2t^(2)hati-(4t+3)hatj`
(4) `vecr=(4t^(3)-2t)hati+hatj`
Are the x and y acceleration components constant? Is acceleration `veca` constant?

Explanation

To determine whether the x and y acceleration components are constant and whether the overall acceleration vector is constant for each of the four cases, we will follow these steps:

### Step 1: Analyze the first case
**Position Equations:**
- \( x = -3t^2 + 4t - 2 \)
- \( y = 6t^2 - 4t \)

**Velocity Components:**
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