An elementary particle is subjected to a displacement of `Deltavecr=2.0hati-4.0hatj+8.0hatk`, ending with the position vector `vecr=4.0hatj-5.0hatk`, in meters. What was the particle's initial position vector?

Explanation

To find the initial position vector of the particle, we can use the relationship between the displacement vector, the final position vector, and the initial position vector. The displacement vector \(\Delta \vec{r}\) is given by:

\[ \Delta \vec{r} = \vec{r}_{\text{final}} - \vec{r}_{\text{initial}} \]

From the problem, we know:

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