The velocity `vecv` of a particle moving in the xy plane is given by `vecv=(6.0t-4.0t^(2))hati+8.0hatj`, with `vecv` in meters per second and `t(gt0)` in seconds. (a) What is the acceleration when t = 2.5 s? (b) When (if ever) is the acceleration zero ? (c) When (if ever) is the velocity zero? (d) When (if ever) does the speed equal 10 m/s?

Explanation

(a) `(-14m//s^(2))hati,` (b) 0.75 s, ( c) it is never zero, (d) 2.2 s