A projectile's launch speed is 6.00 times that of its speed at its maximum height. Find the launch angle `theta_(0)`.

Explanation

To solve the problem, we need to find the launch angle \( \theta_0 \) given that the launch speed \( u \) is 6 times the speed at maximum height.

### Step-by-Step Solution:

1. **Understand the Components of the Launch Speed:**
The launch speed \( u \) can be broken down into horizontal and vertical components:
- Horizontal component: \( u_x = u \cos \theta_0 \)
- Vertical component: \( u_y = u \sin \theta_0 \)
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