Upon spotting an insect on a twig overhanging water, an archer fish squirts water drops at the insect to knock it into the water. Although the insect is located along a straightline path at angle `phi` and distance d, a drop must be launched at a different angle `theta_(0)` if its parabolic path is to intersect the insect. If `phi=36.0^(@)` and d = 0.900 m. what launch angle `theta_(0)` is required for the drop to be at the top of the parabolic path when it reaches the insect?

Explanation

`55.5^(@)`