Home
Class 12
PHYSICS
A body is projected with a velocity of 6...

A body is projected with a velocity of 60 m/s at `30^(@)` to horizontal (assume positive x-axis and positive y axis as horizontal and vertical directions, respectively, and take `g=10m//s^(2)`).

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
Promotional Banner

Topper's Solved these Questions

  • MOTION IN TWO AND THREE DIMENSIONS

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (LINKED COMPREHENSION)|14 Videos
  • MOTION ALONG A STRAIGHT LINE

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS ( Integer Type )|3 Videos
  • OSCILLATIONS

    RESNICK AND HALLIDAY|Exercise Practice Questions|57 Videos

Similar Questions

Explore conceptually related problems

A body is projected with velocity 60m//s at 30^(@) to the horizontal.The velocity of the body after 3 seconds is

A body is projected with an initial velocity 20 m//s at 60^(@) to the horizontal. Its initial velocity vector is "___" (g=10 m//s^(2))

A body is projected with a velocity 30m/s making an angle 53^(@) with the horizontal. The time after which its vertical and horizontal components of velocities will be equal, g=10m/s^(2) (A) (4)/(5)s (B) (3)/(5)s (C) (3)/(4)s (D) (1)/(4)s

A body is projected with a initial velocity of (8hati+6hatj) m s^(-1) . The horizontal range is (g = 10 m s^(-2))

A body is projected with a velocity 30 ms^(-1) at an angle of 30^@ with the vertical. Find (i) the maximum height (ii) time of flight and (iii) the horizontal range of the projectile. Take g=10 m//s^@ .

A body is projected horizontally with a velocity of 39.4m//s from the top of a building . After what time the horizontal and vertical velocities of the body become equal ?

A body is projected from the ground with some speed at some angle with the horizontal. Taking the horizontal and vertical direction to be x and y axis respectively and the point of projection as origin, calculate the minimum speed (in ms^(-1) ) of projection so that it can pass through a point whose x and y coordinates are 30 m and 40 m respectively? Take g=10ms^(-2)

A body is projected with a velocity V = 3 hati + 4 hatj + 12 hatk units. Assume xy plane is horizontal (g=10m/s). The range and maximum height are?

A particle is projected with velocity of 10m/s at an angle of 15° with horizontal.The horizontal range will be (g = 10m/s^2)

A ball is projected vertically up with speed 20 m/s. Take g=10m//s^(2)