Home
Class 12
PHYSICS
The maximum pressure amplitude Delta pm ...

The maximum pressure amplitude `Delta p_m` that the human ear can tolerate in loud sounds is about 28 Pa (which is very much less than the normal air pressure of about `10^5` Pa). What is the displacement amplitude `s_m`for such a sound in air of density `rho= 1.21 kg//m^3`, at a frequency of 1000 Hz and a speed of 343 m/s?

Text Solution

AI Generated Solution

To find the displacement amplitude \( s_m \) for a sound wave given the maximum pressure amplitude \( \Delta p_m \), we can use the relationship between pressure amplitude, displacement amplitude, density of the medium, frequency, and speed of sound. ### Step-by-Step Solution: 1. **Identify the given values:** - Maximum pressure amplitude, \( \Delta p_m = 28 \, \text{Pa} \) - Density of air, \( \rho = 1.21 \, \text{kg/m}^3 \) - Frequency of the sound, \( f = 1000 \, \text{Hz} \) ...
Promotional Banner

Topper's Solved these Questions

  • WAVE - II

    RESNICK AND HALLIDAY|Exercise CHECKPOINTS|4 Videos
  • WAVE - II

    RESNICK AND HALLIDAY|Exercise PROBLEMS|59 Videos
  • VECTORS

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS|39 Videos
  • WAVES-I

    RESNICK AND HALLIDAY|Exercise Practice Questions (Integer Type)|4 Videos

Similar Questions

Explore conceptually related problems

the maximum pressure variation that the human ear can tolerate in loud sound is about 30 N //m^(2) . The corresponding maximum displacement for a sound wave ina air having a frequency of 10^(3) Hz is take velocity of sound in air as 300 m/s and density of air 1.5 kg // m ^(3)

A sound wave having a frequency of 100 Hz and pressure amplitude of 10 pa, then calculate the displacement amplitude (Given speed od sound in air = 340 m/s and density of air = 1.29 kg/m^(3) )

Sound travels with a speed of about 330 m/s. What is the wavelength of sound whose frequency is 660Hz.

Plane harmonic waves of frequency 500 Hz are produced in air with displacement amplitude of 10mum . Given that density of air is 1.29(kg)/(m^3) and speed of sound in air is 340(m)/(s) . Then

The pressure variation that correspond to pain threshold (i.e., the ear can tolerate in loud sound) is about 30 Pa. velocity of sound in water is sqrt(2)xx10^3m//s . The intensity of sound wave produced in water corresponding to loud sound is

A typical loud sound wave with a frequency of 1 Kh_(Z) has a pressure amplitude of about 10 Pa (a) At t = 0 , the pressure is a maximum at some point X_(1) . What is the displacement at that point at t = 0 ? (b) What is the maximum value of the displacement at any time and place/ Take the density of air to be 1.29 kg//m^(3) and speed of sound in air is 340 m//s .

A 10 W source of sound of frequency 1000 Hz sends out wave in air. The displacment amplitude a distance of 10 m from the source is (speed of sound in air = 340 m/s and density of air = 129 kg/m^(3) )

Measurement of sound waves show that the maximum pressure variations in the loudest sound that the ear can tolerate without pain are of the order of 30 Pa. Find the corresponding maximum displacement, if the frequency is 1000 Hz and v = 350 m//s

Two sound waves one in air and the other in fresh water are equal in intensity. (a) Find the ratio of pressure amplitude of the wave in water to that of the wave in air. (b) If the pressure amplitudes of the waves are equal then what will be the ratio of the intensities of the waves. [ V_(sound) = 340 m//s in air & density of air = 1.25 kg//m^(3), V_(sound) = 1530 m//s in water, density of water = 1000 kg//m^(3) ]