An electron is shot into one end of a solenoid.As it enters the uniform magnetic field within the solenoid, its speed is `800 m//s` and its velocity vector makes an angle of `30^(@)` with the central axis of the solenoid.The solenoid carries `4.0 A` current and has `8000` turn along its length.Find number of revolutions made by the electron within the solenoid by the time it emerges from the solenoid's opposite end. (Use charge of mass ratio `e/m` for electron `=sqrt3xx10^(11) C//kg`)Fill your answer in multiple of `10^(3)` (neglect end effect)

Answer

`~~1.62xx10^(6)`