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A steady current I goes through a wire l...

A steady current `I` goes through a wire loop `PQR` having shape of a right angle triangle with `PQ = 3x, PR = 4x and QR = 5x`. If the magnitude of the magnetic field at `P` due to this loop is `k((mu_(0)I)/(48 pi x))`, find the value of `K`.

Text Solution

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The correct Answer is:
`7`
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A steady current I goes through a wire loop P Q R having shepe of a right angle triangle with P Q=3 x, P R=4 x and Q R=5 x . If the magnitude of the magnetic field at P due to this loop is k((mu_(0) I)/(48 pi x)) , then find the value of k .

A wire loop PQR having the shape right-angle triangle with PQ = 3a, PR = 4at and QR=5r carries a steady current I.If the magnitude of the magnetic field at the point P due to this loop is k (mu_(0)I)/(48 pi x) then find the value of k.

Knowledge Check

  • A current /is flowing through the loop. The direction of the current and the shape of the loop are as shown in the figure. The magnetic field at the centre of the loop is (mu_(0)I)/("R") times (MA=R,MB=2R, angleDMA=90^(@)

    A
    `(5)/(16)` ,but of the plane of the paper.
    B
    `(5)/(16)`, but into the plane of the paper.
    C
    `(7)/(16)`,but out of the plane of the paper.
    D
    `(7)/(16)`,but into the plane of the paper.

  • A wire bent in the shape of a regular n-polygonal loop carries a steady current I. Let l be the perpendicular distance of a given segment and R be the distance of vertex both from the centre of the loop. The magnitude of the magnetic field at the centre of the loop is given by -

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    B
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    C
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    D
    `(n mu_(0)I)/(2pi R)cos(pi//n)`

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