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{((0.1)^(2) - (0.01)^(2))/(0.0001) + 1} ...

`{((0.1)^(2) - (0.01)^(2))/(0.0001) + 1}` is equal to

A

`1010`

B

110

C

101

D

100

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \(\frac{(0.1)^2 - (0.01)^2}{0.0001} + 1\), we can follow these steps: ### Step 1: Identify the expression We start with the expression: \[ \frac{(0.1)^2 - (0.01)^2}{0.0001} + 1 \] ### Step 2: Calculate the squares Calculate \((0.1)^2\) and \((0.01)^2\): \[ (0.1)^2 = 0.01 \] \[ (0.01)^2 = 0.0001 \] ### Step 3: Substitute the squares back into the expression Substituting these values back into the expression gives: \[ \frac{0.01 - 0.0001}{0.0001} + 1 \] ### Step 4: Simplify the numerator Now, simplify the numerator: \[ 0.01 - 0.0001 = 0.0099 \] So we have: \[ \frac{0.0099}{0.0001} + 1 \] ### Step 5: Divide the numerator by the denominator Next, we divide \(0.0099\) by \(0.0001\): \[ \frac{0.0099}{0.0001} = 99 \] Thus, the expression simplifies to: \[ 99 + 1 \] ### Step 6: Add 1 to the result Finally, we add \(1\) to \(99\): \[ 99 + 1 = 100 \] ### Final Answer Therefore, the expression \(\frac{(0.1)^2 - (0.01)^2}{0.0001} + 1\) is equal to \(100\). ---
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