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What would be the sum of 1+3+5+7+9+11+13...

What would be the sum of 1+3+5+7+9+11+13+15+…… up to 15th term ?

A

250

B

240

C

225

D

265

Text Solution

AI Generated Solution

The correct Answer is:
To find the sum of the series 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 up to the 15th term, we can use the formula for the sum of an arithmetic series. ### Step-by-step Solution: 1. **Identify the first term (a) and the common difference (d)**: - The first term \( a = 1 \) - The common difference \( d = 3 - 1 = 2 \) 2. **Determine the number of terms (n)**: - We need to find the sum up to the 15th term, so \( n = 15 \). 3. **Use the formula for the sum of the first n terms of an arithmetic series**: The formula for the sum \( S_n \) of the first \( n \) terms of an arithmetic series is given by: \[ S_n = \frac{n}{2} \times (2a + (n - 1)d) \] 4. **Substitute the values into the formula**: - Substitute \( n = 15 \), \( a = 1 \), and \( d = 2 \): \[ S_{15} = \frac{15}{2} \times (2 \times 1 + (15 - 1) \times 2) \] 5. **Calculate the expression inside the parentheses**: - Calculate \( 2 \times 1 = 2 \) - Calculate \( (15 - 1) \times 2 = 14 \times 2 = 28 \) - Now, add these values: \( 2 + 28 = 30 \) 6. **Complete the calculation for \( S_{15} \)**: \[ S_{15} = \frac{15}{2} \times 30 \] - Simplify \( \frac{15 \times 30}{2} = \frac{450}{2} = 225 \) 7. **Final Result**: - Therefore, the sum of the series up to the 15th term is \( 225 \).
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