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A man sold an article at a loss of 20% ....

A man sold an article at a loss of 20% . If he sells the article for Rs 12 more, he would gained 10%. The cost price of the article is

A

Rs 60

B

Rs 40

C

Rs 30

D

Rs 22

Text Solution

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The correct Answer is:
To solve the problem step by step, we will denote the cost price of the article as \( CP = x \). ### Step 1: Determine Selling Price at a 20% Loss The selling price (SP) when the article is sold at a loss of 20% can be calculated using the formula: \[ SP = CP - \text{Loss} \] The loss is 20% of the cost price, which can be expressed as: \[ \text{Loss} = \frac{20}{100} \times x = 0.2x \] Thus, the selling price at a 20% loss is: \[ SP = x - 0.2x = 0.8x \] ### Step 2: Determine Selling Price for a 10% Gain If the man sells the article for Rs 12 more than the previous selling price, the new selling price (SP') can be expressed as: \[ SP' = SP + 12 = 0.8x + 12 \] To find the selling price that gives a 10% gain, we use the formula: \[ SP' = CP + \text{Profit} \] The profit is 10% of the cost price, which can be expressed as: \[ \text{Profit} = \frac{10}{100} \times x = 0.1x \] Thus, the selling price for a 10% gain is: \[ SP' = x + 0.1x = 1.1x \] ### Step 3: Set Up the Equation Now we have two expressions for the new selling price: 1. From the loss scenario: \( SP' = 0.8x + 12 \) 2. From the gain scenario: \( SP' = 1.1x \) Setting these two expressions equal gives us: \[ 0.8x + 12 = 1.1x \] ### Step 4: Solve for x Rearranging the equation to isolate \( x \): \[ 12 = 1.1x - 0.8x \] \[ 12 = 0.3x \] Now, divide both sides by 0.3 to find \( x \): \[ x = \frac{12}{0.3} = 40 \] ### Conclusion The cost price of the article is \( \text{Rs } 40 \). ---
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