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The perimeter of the base of a right cir...

The perimeter of the base of a right circular cylinder is 'a' unit. If the volume of the cylinder is V cubic unit, then the height of the cylinder is

A

`(4a^2v)/(pi)` unit

B

`(4pia^2)/(v)` unit

C

`(pia^2v)/(4)` unit

D

`(4piV)/(a^2)` unit

Text Solution

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The correct Answer is:
To find the height of a right circular cylinder given the perimeter of its base and its volume, we can follow these steps: ### Step 1: Understand the given information We know: - The perimeter (circumference) of the base of the cylinder is \( a \) units. - The volume of the cylinder is \( V \) cubic units. ### Step 2: Relate the perimeter to the radius The formula for the perimeter (circumference) of the base of a cylinder is given by: \[ C = 2\pi r \] where \( r \) is the radius of the base. Since the perimeter is given as \( a \): \[ 2\pi r = a \] From this, we can solve for \( r \): \[ r = \frac{a}{2\pi} \] ### Step 3: Write the formula for the volume of the cylinder The volume \( V \) of a cylinder is given by the formula: \[ V = \pi r^2 h \] where \( h \) is the height of the cylinder. ### Step 4: Substitute the expression for \( r \) into the volume formula Substituting \( r = \frac{a}{2\pi} \) into the volume formula: \[ V = \pi \left(\frac{a}{2\pi}\right)^2 h \] Calculating \( \left(\frac{a}{2\pi}\right)^2 \): \[ \left(\frac{a}{2\pi}\right)^2 = \frac{a^2}{4\pi^2} \] Thus, substituting back into the volume formula gives: \[ V = \pi \cdot \frac{a^2}{4\pi^2} \cdot h \] This simplifies to: \[ V = \frac{a^2 h}{4\pi} \] ### Step 5: Solve for the height \( h \) To find \( h \), we rearrange the equation: \[ h = \frac{4\pi V}{a^2} \] ### Conclusion The height of the cylinder is given by: \[ h = \frac{4\pi V}{a^2} \]
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