Some bricks are arranged in an area measuring 20 cu. m. If the length, breadth and height of each brick is 25 cm, 12.5 cm and 8 cm respectively, then in that pile the number of bricks are (suppose there 1s no gap in between two bricks)

Options

A. 6000
B. 8000
C. 4000
D. 10000

Answer

To solve the problem of finding the number of bricks that can fit in a volume of 20 cubic meters, we will follow these steps:

### Step 1: Calculate the volume of one brick.
The dimensions of the brick are given as:
- Length = 25 cm
- Breadth = 12.5 cm
- Height = 8 cm

The volume \( V \) of a brick can be calculated using the formula:
\[ V = \text{Length} \times \text{Breadth} \times \text{Height} \]
Substituting the values:
\[ V = 25 \, \text{cm} \times 12.5 \, \text{cm} \times 8 \, \text{cm} \]
Calculating this gives:
\[ V = 25 \times 12.5 = 312.5 \, \text{cm}^2 \]
\[ V = 312.5 \times 8 = 2500 \, \text{cm}^3 \]
So, the volume of one brick is \( 2500 \, \text{cm}^3 \).

### Step 2: Convert the total volume from cubic meters to cubic centimeters.
The total volume given is \( 20 \, \text{m}^3 \). We need to convert this to cubic centimeters:
\[ 1 \, \text{m}^3 = 100^3 \, \text{cm}^3 = 1000000 \, \text{cm}^3 \]
Thus,
\[ 20 \, \text{m}^3 = 20 \times 1000000 \, \text{cm}^3 = 20000000 \, \text{cm}^3 \]

### Step 3: Calculate the number of bricks that can fit in the total volume.
To find the number of bricks, we divide the total volume by the volume of one brick:
\[ \text{Number of bricks} = \frac{\text{Total Volume}}{\text{Volume of one brick}} = \frac{20000000 \, \text{cm}^3}{2500 \, \text{cm}^3} \]
Calculating this gives:
\[ \text{Number of bricks} = \frac{20000000}{2500} = 8000 \]

### Final Answer:
The number of bricks that can fit in the pile is **8000**.

---