A, B and C are three students. A got 18% more marks than B and 12% less than c . If B got 220 marks, how much marks C has got ?

Options

A. 230
B. 295
C. 240
D. 290

Answer

To find out how many marks C has got, we can follow these steps:

### Step 1: Calculate A's Marks
Since B got 220 marks and A got 18% more marks than B, we can calculate A's marks as follows:

\[ \text{A's Marks} = \text{B's Marks} + 18\% \text{ of B's Marks} \]

\[ \text{A's Marks} = 220 + \left(\frac{18}{100} \times 220\right) \]

Calculating \(18\% \text{ of } 220\):

\[ \frac{18}{100} \times 220 = 39.6 \]

So,

\[ \text{A's Marks} = 220 + 39.6 = 259.6 \]

### Step 2: Calculate C's Marks
A got 12% less marks than C. Therefore, we can express C's marks in terms of A's marks:

\[ \text{A's Marks} = \text{C's Marks} - 12\% \text{ of C's Marks} \]

Let C's marks be \(C\). Then we can write:

\[ 259.6 = C - \left(\frac{12}{100} \times C\right) \]

This simplifies to:

\[ 259.6 = C \left(1 - \frac{12}{100}\right) \]

\[ 259.6 = C \left(\frac{88}{100}\right) \]

Now, solving for \(C\):

\[ C = \frac{259.6 \times 100}{88} \]

Calculating \(C\):

\[ C = \frac{25960}{88} = 295 \]

### Final Answer
C has got **295 marks**.

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