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In what ratio does the point T(x, 0) div...

In what ratio does the point T(x, 0) divide the segment joining the points S(-4.-1) and U (1,4)?

A

`1:4`

B

`4:1`

C

`1:2`

D

`2:1`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio in which the point T(x, 0) divides the segment joining the points S(-4, -1) and U(1, 4), we can use the section formula. The section formula states that if a point divides a line segment joining two points in the ratio m:n, then the coordinates of the point can be expressed as: \[ \left( \frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n} \right) \] Here, we have: - Point S(-4, -1) as (x1, y1) - Point U(1, 4) as (x2, y2) - Point T(x, 0) as (x, y) We need to find the ratio \( m:n \) such that the y-coordinate of point T is 0. ### Step 1: Set up the equation for the y-coordinate Using the section formula for the y-coordinate, we have: \[ 0 = \frac{m \cdot 4 + n \cdot (-1)}{m+n} \] ### Step 2: Simplify the equation Multiplying both sides by \( m+n \) to eliminate the denominator gives: \[ 0 = 4m - n \] ### Step 3: Rearranging the equation Rearranging the equation gives: \[ n = 4m \] ### Step 4: Express the ratio Now, we can express the ratio \( m:n \): \[ \frac{m}{n} = \frac{m}{4m} = \frac{1}{4} \] Thus, the ratio \( m:n \) is \( 1:4 \). ### Conclusion The point T(x, 0) divides the segment joining points S(-4, -1) and U(1, 4) in the ratio \( 1:4 \). ---
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