If a waveform has the equation `y_1=A_1 sin (omegat-kx)` & `y_2=A_2 cos (omegat-kx)` , find the equation of the resulting wave on superposition.

Two waves are given as y_1=3A cos (omegat-kx) and y_2=A cos (3omegat-3kx) . Amplitude of resultant wave will be ____

Two waves are given as y_1=3A cos (omegat-kx) and y_2=A cos (3omegat-3kx) . Amplitude of resultant wave will be ____

Two waves are represented by the equations y_1=a sin omega t and y_2=a cos omegat . The first wave

On the superposition of the two waves given as y_1=A_0 sin( omegat-kx) and y_2=A_0 cos ( omega t -kx+(pi)/6) , the resultant amplitude of oscillations will be

On the superposition of the two waves given as y_1=A_0 sin( omegat-kx) and y_2=A_0 cos ( omega t -kx+(pi)/6) , the resultant amplitude of oscillations will be

Two sinusoidal waves are superposed. Their equations are y_(1)=Asin(kx-omegat+(pi)/(6))and y_(2)=Asin(kx-omegat-(pi)/(6)) the equation of their resultant is

Two sinusoidal waves are superposed. Their equations are y_(1)=Asin(kx-omegat+(pi)/(6))and y_(2)=Asin(kx-omegat-(pi)/(6)) the equation of their resultant is

Two waves are given by y_(1)=asin(omegat-kx) and y_(2)=a cos(omegat-kx) . The phase difference between the two waves is -

Two waves are given by y_(1)=asin(omegat-kx) and y_(2)=a cos(omegat-kx) . The phase difference between the two waves is -

Two waves are given by y_(1)=asin(omegat-kx) and y_(2)=a cos(omegat-kx) . The phase difference between the two waves is -