The mean and standard deviation of a binomial variate X are 4 and 3 respectively. Then, `P(Xge1)` is equal to

The mean and standard deviation of a binomial variate X are 4 and sqrt(3) respectively. Then , P(Xge1)=

The mean and standard deviation of a binomial variate X are 4 and sqrt(3) respectively. Then , P(Xge1)=

The mean and standard deviation of a binomial variate X are 4 and sqrt3 respectively. Then P(X= ge 1)=

Mean and variance of a binomial variate X are 4 and 2 respectively Then P (X =1 )= ……

If the mean and variance of a binomial variate X are 8 and 4 respectively then P(X lt 3)=

If the mean and standard deviation of a binomial distribution are 12 and 2 respectively . Then the value of its parameter p is ………….. .

The mean and standard deviation of a binomial variate X are respectively 6 and 2. Find (i) the probability mass function (ii) P(X=3) (iii) P(X ge 2) .