Home
Class 12
PHYSICS
A radiation of wave length 2500A^(0) is ...

A radiation of wave length `2500A^(0)` is incident on a metal plate whose work function is `3.5eV`. Then the potential required to stop the fastest photo electrons emitted by the surface is `(h=6.63xx10^(-34)Js & c=3xx10^(8)m//s)`

Promotional Banner

Similar Questions

Explore conceptually related problems

Radiation of energy 6.5 eV is incident on a metal surface whose work function is 4.2 eV. What is the potential difference that should be applied to stop the fastest photoelectrons emitted by the metal surface ?

A light of wavelength 500 nm is incident on a sensitive plate of photoelectric work function 1.235 eV. The kinetic energy of the photo electrons emitted is be (Take h = 6.6 xx 10^(-34) Js)

A light of wavelength 500nm is incident on a sensitive plate of photoelectric work function 1.235 eV. The kinetic energy of the photo electrons emitted is be ( Take h = 6.6 xx 10^(-34)Js)

The work function of a metal is 2.5eV . The maximum kinetic energy of the photoelectrons emitted if a radiof wavelength 3000A^(0) falls on it is (h=6.63xx10^(-34)Js & c=3xx10^(8)m//s)

The work function of nickle is 5eV . When light of wavelength 2000A^(0) falls on it, emits photoelectrons in the circuit. The the potential difference necessary to stop the fastest electrons emitted is (given h=6.67xx10^(-34) Js )