If X is a Poisson variate such that `P(X=2)=9P(X=4)`, then the mean and variance of X are

If X is a Poisson variate such that P(X=3)=P(X=2) , then P(X=4)=

If X is a Poisson variate such that P(X=0)=P(X=1) , then the parameter lambda=

If X is a Poisson variate such that P(X=0)=P(X=1) , then the parameter lambda=

If X is a Poisson variate such that P(X=2)=9P(X=4)+90P(X=6) , then mean of X is

If a random variable X has a Poisson distribution such that P(X=2)=P(X=3) then its mean and variance are

A : If X is a poisson variate such that P(X=2)=9P(X=4) then variance =2//3 R : The variancen of a poisson variate with parameter lambda .

If X is a Poisson variate such that P(X=2)=9P(X=4)+90P(X=6) , then mean of X is a) 1 b) 2 c) 1/2 d) 3/2

If X is a poisson variate such that P(X=0)=P(X=1)=K , then show that K = 1/e