cos theta-cos2 theta=sin3 theta

Simplify: (sin8 theta cos theta-sin6 theta cos3 theta)/(cos2 theta cos theta-sin3 theta sin4 theta)

If theta=7.5^(@) Find the value of quad sin8 theta*cos theta-sin6 theta cos3 thetacos2 theta*cos theta-sin3 theta*sin4 theta

cos theta-cos3 theta+cos5 theta-cos7 theta=4sin theta sin4 theta cos2 theta

Let f_(n)(theta)=(sin theta+sin2 theta+sin3 theta++sin n theta)/(cos theta+cos2 theta+cos3 theta++cos n theta)

The value of (2(sin2 theta+2cos^(2)theta-1))/(cos theta-sin theta-cos3 theta+sin3 theta)=

sin theta+sin2 theta+sin3 theta=sin alpha and cos theta+cos2 theta+cos3 theta=cos alpha then theta is equal to

If sin theta+sin2 theta+sin3 theta=sin alpha and cos theta+cos2 theta+cos3 theta=cos alpha, then theta is equal to

Smallest positive value of theta satisfying 8sin theta cos2 theta sin3 theta cos4 theta=cos6 theta is

2(cos theta+cos2 theta)+(1+2cos theta)sin2 theta=2sin theta

(sin3 theta+cos3 theta)/(cos theta-sin theta)=1+2xx sin2 theta