[" If "sin(A+B+C)=1,tan(A-B)=(1)/(sqrt(3))" and "],[sec(A+C)=2" then "]

In an acute angled DeltaABC,sec(B+C-A)=2 and tan(C+A-B)=(1)/(sqrt3) . Find the three angles of DeltaABC.

In Delta ABC if sin B cos C=(sqrt(3)-1)/(sqrt(3)) and sin C cos B=(1)/(sqrt(3)), then the triangle is

In Delta ABC if sin B cos C=(sqrt(3)-1)/(sqrt(3)) and sin C cos B=(1)/(sqrt(3)), then the triangle is

Each angle A, B,C of the triangle ABC is acute and sin (B+C-A)=1 , tan (C+A-B)= sqrt(3) , find A,B and C.

In an acute angled triangle ABC, if tan(A+B-C)=1 and ,sec(B+C-A)=2, find the value of A,B and C.

if sin((c)/(2))=(a-b)/(2sqrt(ab))tan theta prove that c=(a-b)sec theta

In triangleABC, angleA=60, b = sqrt(3)+1 and c = sqrt(3)-1 then the value of tan ((B-C)/2) is-

A: int (1)/(3+2 cos x)dx=(2)/(sqrt(5))"Tan"^(-1)((1)/(sqrt(5))"tan" (x)/(2))+c R: If a gt b then int (dx)/(a+b cosx)=(2)/(sqrt(a^(2)-b^(2)))Tan^(-1)[(sqrt(a-b))/(a+b)"tan"(x)/(2)]+c