The displacement of two particles executing SHM are represented by equations, `y_(1)=2 sin (10 t + theta), y_(2)=3 cos 10 t`. The phase difference between the velocity of these particles is

The displacement of two particles executing S.H.M are represented by y_(1) = a sin(wt + phi) and y_(2) = a cos w t . The phase difference between the velocities of these particles is

Two simple harmonic motion are represented by equations y_(1) = 4 sin (10 t + phi) rArr y_(2) = 5 cos 10t What is the phase difference between their velocities ?

Two simple harmonic motion are represented by equations y_(1) = 4 sin (10 t + phi) rArr y_(2) = 5 cos 10t What is the phase difference between their velocities ?

The equation of the displacement of two particles making SHM are represented by y_(1) = a sin (omegat +phi) & y_(2) - a cos (omegat) . Phase difference between velocities of two particles is

The SHMs are represent by the equation y_(1)=0.1sin(100pit+(pi)/(3))&y_(2)=0.1 cos pit . The phase difference of the velocity of particle is

The displacement of two identical particles executing SHM are represented by equations. x_(1) = 4sin(10t+pi/6) and x_(2)=5cosepsilont For what value of epsilon energy of both the particles is same?

The phase difference between the displacement and velocity of a particle in SHM is