" If "|z^(2)-1|=|z|^(2)+1" then "''z''" lies on "

If |z^(2)-1|=|z^(2)|+1 , then z lies on

If |z^(2)-1|=|z|^(2)+1, then show that z lies on the imaginary axis.

If 1z^(2)-1|=|z|^(2)+1, then z lies on (1)An ellipse (3)A circle 89.(2) The imaginary axis (4) The real axis

If a complex number |z ^2-1|=|z|^2+1 , then z lies on :

If |z^2-1|=|z|^2+1 , then show that z lies on the imaginary axis.

If abs(z^2-1)=absz^2+1 , then z lies on

If abs(z^2-1) =(abs(z))^2+1 , then z lies on

If |z-(2)/(z)|=1 then |z| lies in