tan^(2)theta=(8)/(7)" then "((1+sin theta)(1-sin theta))/((1+cos theta)(1-cos theta))=.........

If theta is an acute angle such that tan^(2)theta=(8)/(7) then the value of ((1+sin theta)(1-sin theta)/((1+cos theta)(1-cos theta)) is (7)/(8)(b)(8)/(7)(c)(7)/(4)(d)(64)/(49)

If cot theta=(7)/(8), evaluate.1.)((1+sin theta)(1-sin theta))/((1-cos theta)(1+cos theta))

If cot theta=7/8 , evaluate:- ((1+sin theta)(1-sin theta))/ ((1+cos theta)(1-cos theta))

If cot theta=(7)/(8) then find the value ((1-sin theta)(1+sin theta))/((1-cos theta)(1+cos theta))

If quad cot theta=(7)/(8) ,evaluate: ( i ) ((1+sin theta)(1-sin theta))/((1+cos theta)(1-cos theta)) (ii)

(sin theta+sin2 theta)/(1+cos theta+cos2 theta)=tan theta

(sin theta+sin2 theta)/(1+cos theta+cos2 theta)=tan theta

If cot theta = (7)/(8) , then the value of ((1 + sin theta)(1- sin theta))/((1 + cos theta)(1- cos theta)) = _________

(1)/(1-sin theta)-(1)/(1+sin theta)=(2tan theta)/(cos theta)