The potential energy `U`(in `J`) of a particle is given by `(ax + by)`, where `a` and `b` are constants. The mass of the particle is `1 kg` and `x` and `y` are the coordinates of the particle in metre. The particle is at rest at `(4a, 2b)` at time `t = 0`.
Find the speed of the particle when it crosses x-axis

The potential energy U (in J ) of a particle is given by (ax + by) , where a and b are constants. The mass of the particle is 1 kg and x and y are the coordinates of the particle in metre. The particle is at rest at (4a, 2b) at time t = 0 . Find the acceleration of the particle.

The potential energy U (in J ) of a particle is given by (ax + by) , where a and b are constants. The mass of the particle is 1 kg and x and y are the coordinates of the particle in metre. The particle is at rest at (4a, 2b) at time t = 0 . Find the coordinates of the particle at t =1 second.

The potential energy of a particle is given by formula U=100-5x + 100x^(2), where U and 'x' are in SI unit .if mass of particle is 0.1 Kg then find the magnitude of its acceleration

The potential energy varphi , in joule, of a particle of mass 1kg , moving in the x-y plane, obeys the law varphi=3x+4y , where (x,y) are the coordinates of the particle in metre. If the particle is at rest at (6,4) at time t=0 , then

The potential energy varphi , in joule, of a particle of mass 1kg , moving in the x-y plane, obeys the law varphi=3x+4y , where (x,y) are the coordinates of the particle in metre. If the particle is at rest at (6,4) at time t=0 , then

The potential energy U in joule of a particle of mass 1 kg moving in x-y plane obeys the law U = 3x + 4y , where (x,y) are the co-ordinates of the particle in metre. If the particle is at rest at (6,4) at time t = 0 then :

The potential energy U in joule of a particle of mass 1 kg moving in x-y plane obeys the law U = 3x + 4y , where (x,y) are the co-ordinates of the particle in metre. If the particle is at rest at (6,4) at time t = 0 then :

The potential energy function of a particle due to some gravitational field is given by U=6x+4y . The mass of the particle is 1kg and no other force is acting on the particle. The particle was initially at rest at a point (6,8) . Then the time (in sec). after which this particle is going to cross the 'x' axis would be: