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" 1."sin40^(@)35cos19^(@)25+cos40^(@)35^...

" 1."sin40^(@)35cos19^(@)25+cos40^(@)35^(1)sin19^(@)25=

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sin40^(@)35'cos19^(@)25'+cos40^(@)35'sin19^(@)25 is equal to

cos20^(@)cos40^(@)-sin5^(@)sin25^(@)=

(cos20^(@)35')/(sin69^(@)25') is

sin(40^@25')cos(19^@35')+cos(40^@25')sin(19^@35')=

Evaluate : sin50^(@)cos40^(@)+cos40^(@)+cos50^(@)sin40^(@)

Evaluate : sin50^(@)cos40^(@)+cos40^(@)+cos50^(@)sin40^(@)

(sin19^(@))/(cos71^(@))+(cos73^(@))/(sin17^(@))

sin25^(@)cos115^(@)=(1)/(2)(sin40^(@)-1)

(sin70^(@)+cos40^(@))/(cos70^(@)+sin40^(@))=?

(sin70^(@)+cos40^(@))/(cos70^(@)+sin40^(@))=