[" In "/_ABC,(a)/(cos A)=(b)/(cos B)=(c)/(cos C)," if "b=2," then the "],[" area of the triangle is (in sq.units) "]

In Delta ABC,(a)/(cos A)=(b)/(cos B)=(c)/(cos c); If b=2 'then the area of the triangle is

In Delta ABC , (a)/( cos A) = (b) /( cos B ) = ( c ) /( cos C ) , If b= 2 then the area of the triangle is

in a triangle ABC , ( cos A)/(a) = (cos B )/( b) = ( cos C )/( c ) if a=(1 )/( sqrt(6)) then the area of the triangle ( in square units ) is

In a triangle ABC, if (cos A)/(a) =(cos B)/(b ) =(cos C)/(c) and the side a=2, then the area of the triangle is-

In Delta ABC, (b-a cos C)/(c-a cos B)=

If in a Delta ABC,(cos A)/(a)=(cos B)/(b)=(cos C)/(c), then find the measures of angles A,B,C.

In a triangle ABC,if (cos A)/(a)=(cos B)/(b)=(cos C)/(c) and the side a=2 then area of triangle is and the side a=2