[" If "a,beta,y" are the lengths of "],[" the altitudes of "Delta ABC," then "],[(cos A)/(alpha)+(cos B)/(beta)+(cos C)/(gamma)=]

If alpha,beta,gamma are the lengths of the altitudes of Delta ABC, then (cos A)/(alpha)+(cos B)/(beta)+(cos C)/(gamma)=

If alpha,beta,gamma are the lengths of the altitudes of Delta ABC , then cosA/alpha+cosB/beta+cosC/gamma=

If alpha, beta , gamma are the lengths of the altitudes of Delta ABC , " then " alpha ^(-2) +beta ^(-2) +gamma^(-2) =

IF alpha,beta,gamma are the lengths of the altitudes of Delta ABC , then 1/alpha+1/beta-1/gamma-(2ab)/((a+b+c)Delta)cos^2""C/2=

If alpha,beta, gamma are the lengths of altitudes of Delta ABC , then alpha^-2+ beta^-2+ gamma^-2 =

If alpha,beta,gamma are the angles of a triangle and system of equations cos(alpha-beta)x+cos(beta-gamma)y+cos(gamma-alpha)z=0cos(alpha+beta)x+cos(beta+gamma)y+cos(gamma+alpha)z=0sin(alpha+beta)x+sin(beta+gamma)y+sin(gamma+alpha)z=0 has non-trivial solutions,then triangle is necessarily a.equilateral b.isosceles c.right angled

If alpha,beta,gamma are the angles of a triangle and system of equations cos(alpha-beta)x+cos(beta-gamma)y+cos(gamma-alpha)z=0 cos(alpha+beta)x+cos(beta+gamma)y+cos(gamma+alpha)z=0 sin(alpha+beta)x+sin(beta+gamma)y+sin(gamma+alpha)z=0 has non-trivial solutions, then triangle is necessarily a. equilateral b. isosceles c. right angled "" d. acute angled

If alpha,beta,gamma are the angles of a triangle and system of equations cos(alpha-beta)x+cos(beta-gamma)y+cos(gamma-alpha)z=0 cos(alpha+beta)x+cos(beta+gamma)y+cos(gamma+alpha)z=0 sin(alpha+beta)x+sin(beta+gamma)y+sin(gamma+alpha)z=0 has non-trivial solutions, then triangle is necessarily a. equilateral b. isosceles c. right angled "" d. acute angled

If alpha,beta,gamma are the angles of a triangle and system of equations cos(alpha-beta)x+cos(beta-gamma)y+cos(gamma-alpha)z=0 cos(alpha+beta)x+cos(beta+gamma)y+cos(gamma+alpha)z=0 sin(alpha+beta)x+sin(beta+gamma)y+sin(gamma+alpha)z=0 has non-trivial solutions, then triangle is necessarily a. equilateral b. isosceles c. right angled "" d. acute angled

Given (b+c)/(11) = (c+a)/(12) = (a+b)/(13) for a Delta ABC with usual notation. If (cos A)/(alpha) = (cos B)/(beta) = (cos C)/(gamma) , then the ordered triad (alpha, beta, gamma) has a value: