" In "Delta ABC,(a+b+c)(tan(A)/(2)+tan(B)/(2))=

In a Delta ABC sum(b+c)(tan A)/(2)tan((B-C)/(2))=

In Delta ABC, tan""(A)/(2)+tan ""(B)/(2)=

* In a Delta ABC,If tan((A)/(2)),tan((B)/(2)),tan((C)/(2)) are in H.P.then a,b,c are in ,tan((C)/(2))

In Delta ABC ( tan ""(A)/(2) - tan ""(B) /(2)) /( tan ""(A)/(2) +tan ""(B)/(2)) =

In Delta ABC, if tan ""(A)/(2), tan""(B)/(2) , tan""(C)/(2) are in A.P. then cos A , cos B , cos C are in

In Delta ABC, (b+c-a) tan (A//2) =

Show that in any triangle ABC,(a+b+c)(tan((A)/(2))+tan((B)/(2)))=2c cot((C)/(2))

In Delta ABC if tan((A)/(2))tan((B)/(2))+tan((B)/(2))tan((C)/(2))=(2)/(3) then a+c

In Delta ABC,tan,(A)/(2)tan,(B)/(2)tan,(C)/(2)=sqrt((1-(a)/(s))(1-(b)/(s)(1-(c)/(s))))

In Delta ABC , if x=tan((B-C)/(2))tan.(A)/(2),y=tan((C-A)/(2))tan.(B)/(2) and z=tan((A-B)/(2))tan.(C)/(2) then (x+y+z)= .