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In a triangle ASBC, let /C=pi/2. If r is...

In a triangle ASBC, let `/_C=pi/2. If r` is the in radius and R is the circumrdius of the triangle then `2(r+R)` is equal to (A) `a+b` (B) `b+c` (C) `c+a` (D) `a+b+c`

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