`sectheta+tantheta=tan(pi/4+theta/2)`

Prove that: (sectheta-tantheta)/(sectheta+tantheta)=1-2sectheta.tantheta+2tan^(2)theta

Prove that: sqrt((1-sintheta)/(1+sintheta)) ={sectheta-tantheta} ,if -pi/2 = -sectheta+tantheta , if pi/2 < theta < (3pi)/2

The locus of the point (sectheta+tantheta,sectheta-tantheta) where theta is parameter, is

If sectheta+tantheta=1/2 then sectheta-tantheta =…………..

If A=[[sectheta, tantheta], [tantheta, sectheta]] , then

(i) (1)/(sectheta-"tan"theta)=(1+"sin"theta)/(costheta)=sectheta+"tan"theta (ii) (1)/(sectheta+"tan"theta)=(1-"sin"theta)/(costheta)=sectheta-"tan"theta

If sectheta+tantheta=3 then sectheta-tantheta = …………….

Evaluate : |A| = [[sectheta , tantheta ],[tantheta ,sectheta]]

If tantheta+sectheta=8 then sectheta-tantheta is