[" If we plot a graph between "],[" log "K" and "1/T" by Arrhenius "],[" equation,the slope is "]

The slope of the graph drawn between ln k and 1/T as per Arrhenius equaiton gives the value (R= gas constant, E_(a)= Activation energy) .

If a graph is plotted between Ln K and 1//T for the first order reaction, the slope of the strainght line so obtained is given by-

If a graph is plotted between ln k and 1//T for the first order reaction, the slope of the straight line so obtained is given by

In the graph of Arrhenius equation, the intercept and slope are

The graph between the log K versus 1/T is a straight line. The slope of the line is

According to Arrhenius equation, the slope of log k vs 1/T plot is

A graph plotted between log k vs (1)/(T) is represented by

The graph between. The log K verrus (1)/(T) is a straight line. The slope of the line is