Vectors a and b are inclined at an angle `theta=120^(@)`. If `|a|=1, |b|=2`, then `[(a+3b)xx(3a+b)]^(2)` is equal to

Vectors veca and vecb are inclined at an angle theta = 120^(@) . If |veca|=1,|vecb|=2, "then" [(veca+3vecb)xx(3veca-vecb)]^(2) is equal to

Vectors vec a and vec b are inclined at an angle theta=120^@ . If |vec a|=1 |vec b|=2 then [(vec a+ 3 vec b) times (3 vec a - vec b)]^2 is a)190 b)275 c)300 d)192

Vectors veca and vec b are inclined at an angle theta = 120^@ . If |veca| = |vecb| = 2 , then [(veca + 3vecb) xx (3veca + vecb)]^2 is equal to

vec a and vec b are inclined at an angle theta=30^(@) If |vec a|=1,|vec b|=2 then |(vec a+3vec b)xx(3vec a-vec b)|^(2)=

vectors veca and vecb are inclined at an angle theta = 60^(@). " If " |veca|=1, |vecb| =2 , " then " [ (veca + 3vecb) xx ( 3 veca -vecb)] ^(2) is equal to

vectors veca and vecb are inclined at an angle theta = 60^(@). " If " |veca|=1, |vecb| =2 , " then " [ (veca + 3vecb) xx ( 3 veca -vecb)] ^(2) is equal to

Vectors vec a\ a n d\ vec b are inclined at angel theta=120^0 . If | vec a|=1,\ | vec b|=2,\ then [( vec a+3 vec b)xx(3 vec a- vec b)]^2 is equal to 300 b. 235 c. 275 d. 225