A 10 kg satellite circles earth once every 2 hrs in an orbit having a radius of 8000 Km . Assuming that bohr 's angular momentum postulate applies to satellites just as it does to an electron in the hydrogen atom , find the quantum number of the orbit of the satellite

Explanation

`m= 10 kg and r_n = 8 xx 10^6 m`
` T= 7200 s`
` mv_n r_n =(n h)/( 2 pi)`
` v_n=(2 pi r_n ) /(t)`
the quantum number of the orbit of the satellite `n= (2 pi r_n ) ^2 xx (m )/( (T xx h ))`
` n= (2 pi xx 8xx 10^6) ^2 xx (10)/((7200 xx 6.64 xx 10^(-34)))=5.3 xx 10^(45)`