CO(g), `CO_(2) (g),N_(2)O(g)` एवं `N_(2)O_(4)(g)` की विरचन एन्थैल्पी क्रमशः -110, -393, 81 एवं 9.7 k J `mol^-1` हैं। अभिक्रिया `N_2O_(4)(g) +3CO(g)toN_(2)O(g)+3CO_(2)(g)` के लिए `Delta_(r)H` का मान ज्ञात कीजिए।

Explanation

`Delta_(f)HCO_(2) (g) =-393 kJmol^(-1)`
`Delta_(f)HN_(2)O(g) =81kJmol^(-1)`,
`Delta_(f)H N_(2)O_(4) (g) = 9.7kJmol^(-1)`
अभिक्रिया `N_(2)O_(4)(g)+ 3CO_(2(g))`के लिए
`Delta_(r)H = sumDelta_(f)H` (उत्पाद) - `sumDelta_(f)H` (अभिकारक)
` = [3Delta_(f)H(CO_(2))+ Delta_(f)H(N_(2)O)] - [Delta_(f)H(N_(2)O_(4)+3Delta_(f)H(CO)]`
[3(-393)+81]-[9.7+3(-110)]
=-1098+320.3
=-777.7kJ`mol^(-1)`