`a^(3)-9b^(3)+(a+b)^(3)`

Simplify using following identiy: (a +- b) (a^(2) ab + b^(2)) = a^(3) +- b^(3) ((a)/(3)-3b) ((a^(2))/(9) + ab + 9b^(2))

(2a^(3)-b^(3))^(3)-b^(9)

If a+b+c=27 then (a-7)^(3)+(b-9)^(3)+(c-11)^(3)-3(a-7)(b-9)(c-11)=

(5a-7b)^(3)+(9c-5a)^(3)+(7b-9c)^(3)

If a+b+c=9 and ab+bc+ca=26 find the value of a^(3)+b^(3)+c^(3)-3abc

If a + b + c = 9 and ab + bc + ca = 18, then the value of a^(3)+b^(3)+c^(3) + 3abc is :