The image (or reflection) of the point (1,2-1) in the plane `vecr.(3hati-5hatj+4hatk)=5` is

Find the image of the point (1, 3, 4) in the plane vecr.(2hati-hatj+hatk)+3=0

Find the distance of the point (3,4,5) from the plane vecr.(2hati-5hatj+3hatk)=13

Image of point (1,3,a) in the plane vecr.(2hati-hatj+hatk)-b=0 is (-3,5,2) then abs(a+b)

Find the image of the point hati+3hatj+4hatk in the plane vecr.(2hati-hatj+hatk)+3=0 .

Find the distance of the point (hati+2hatj-3hatk) from the plane vecr.(2hati-5hatj-hatk)=4 .

Find the distance of the point (2hati-hatj-4hatk) from the plane vecr.(3hati-4hatj+12hatk)=9 .

Find the vector equation of the line passing through (1, 2, 3) and parallel to each of the planes vecr = (hati-hatj+2 hatk)= 5" and "vecr *(3hati- hatj+hatk)= 6 . Also find the point of intersection of the line thus obtained with the plane vecr * (2hati-hatj+hatk)= 4 .

The vector parallel to the line of intersection of the planes vecr.(3hati-hatj+hatk) = 1 and vecr.(hati+4hatj-2hatk)=2 is :

The vector parallel to the line of intersection of the planes vecr.(3hati-hatj+hatk) = 1 and vecr.(hati+4hatj-2hatk)=2 is :

Find the perpendicular distance from the point (2hati-hatj+4hatk) to the plane vecr.(3hati-4hatj+12hatk) = 1 .